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PHP development / คุณ Davinci หรือ โปรแกรมเมอร์ท่านอื่นช่วยแนะนำหน่อยครับ
Anan
Anan
Sat 11 Nov 2006 16:38:33

สวัสดีครับคุณ Davinci หรือ โปรแกรมเมอร์ท่านอื่นครับ

ผมมี error พยายามหาก็หาไม่เจอครับ กรุณาช่วยแนะนำด้วยนะครับ

Parse error: parse error, unexpected '>' in c:\appserv\www\web\post_2\post_dirpost.txt on line 45

โปรแกรมเขียนดังนี้ครับ

<meta http-equiv="Content-Type"  content="text/html; charset=tis-620"> 
<center>
<?

$pagelen = 10 ;
$_GET["page"] = $_REQUEST['page'];
if (empty($_GET["page"] )) { $_GET["page"] =1; }

require("config.inc.php");
if(!$link)
{
print("Error");
}
else
{
mysql_select_db("fooddirectories_com_-_company",$link);

 $sql="SELECT COUNT(company) AS num FROM company WHERE agri=1";
 $res=mysql_query($sql, $link);
 $row = mysql_fetch_array($res, MYSQL_ASSOC);
 echo"<font color='#0000CD' face='verdana' size='1'>";
 echo"<b>";
 echo $row["num"];
 echo"<font color='228B22' face='verdana' size='1'>  Agricultural product companies";
 echo"</b><br><br>";
 

$sql = "SELECT company, country, email1 FROM company WHERE agri=1 order by company asc";
$res=mysql_query($sql,$link);
$num_rows=mysql_num_rows($res);

$totalpage = ceil($num_rows / $pagelen);

$goto = ($_GET["page"] -1) * $pagelen;
$sql = "SELECT company, country, email1 FROM company WHERE agri=1 order by company asc LIMIT $goto , $pagelen ";

$res = mysql_query( $sql,$link );
  echo"<table border=0 cellpadding=3 cellspacing=0>";
  echo"<tr><td><font color='#8B0000' face='verdana' size='1'><center><b>Company</b></center></font></td>";
  echo"<td><font color='#8B0000' face='verdana' size='1'><center><b>Country</b></center></font></td>";
  echo"<td><font color='#8B0000' face='verdana' size='1'><center><b>Email</b></center></font></td></tr>";
while($row=mysql_fetch_array($res,MYSQL_ASSOC))
 {
echo"<tr><td><font color='#8B0000' face='verdana' size='1'>
<a href=\"javascript:;\" onclick=\"window.open('popup_company.php?email1=".$row["email1"]."', 'pw', 'width=400,height=350,toolbars=no,status=no');\">
".$row["company"]."</a></font></td>";


echo"<td><font color='#8B0000' face='verdana' size='1'>".$row["country"]."</font></td>";
echo"<td><font color='#8B0000' face='verdana' size='1'>".((isset($_SESSION["active"])&&$_SESSION["active"]="ok")?$row["email1"]:"Member only")."</font></td></tr>";
}
echo "</table>";

if ($_GET["page"] > 1) {
 $back = $_GET["page"]  - 1;
 echo "<a href=\"".$_SERVER["PHP_SELF"]."?page=".$i."&alphabet=".$_GET["alphabet"]."\"><img src=\"main_first.gif\" border=\"0\" align=\"absmiddle\" alt=\"First\"></a>\n";
 echo "<a href=\"".$_SERVER["PHP_SELF"]."?page=".$i."&alphabet=".$_GET["alphabet"]."=".$back."\"><img src=\"main_previous.gif\" border=\"0\" align=\"absmiddle\" alt=\"Previous\"></a>";
}

for($i=1 ; $i<=$totalpage ; $i++) {
 if ($i == $_GET["page"] ) {
  echo " [<b><font size =+1 color=#990000>$i</font></b>] \n";
 } else  {
  echo " <a href=\"".$_SERVER["PHP_SELF"]."?page=".$i."&alphabet=".$_GET["alphabet"]."\">".$i."</a>";
 }
}

if ($_GET["page"] < $totalpage) {
 $next = $_GET["page"]  +1;
 echo "<a href=\"".$_SERVER["PHP_SELF"]."?page=".$i."&alphabet=".$_GET["alphabet"]."=".$next."\"><img src=\"main_next.gif\" border=\"0\" align=\"absmiddle\" alt=\"Next\"></a>";
 echo " <a href=\"$PHP_SELF?page=".$totalpage."\"><img src=\"main_last.gif\" border=\"0\" align=\"absmiddle\" alt=\"Last\"></a> \n";
   }
}
 
?>

กรุณาช่วยแนะนำด้วยนะครับ

อนันต์

Anan
Anan
Sat 11 Nov 2006 17:02:01

ขอบคุณครับ แก้ได้แล้วครับ

อนันต์

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